5x^2+2x-4/x^2-2x=3

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Solution for 5x^2+2x-4/x^2-2x=3 equation: 



5x^2+2x-4/x^2-2x=3

We move all terms to the left:

5x^2+2x-4/x^2-2x-(3)=0



Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R



We add all the numbers together, and all the variables

5x^2-4/x^2-3=0

We multiply all the terms by the denominator


5x^2*x^2-3*x^2-4=0

We add all the numbers together, and all the variables

-3x^2+5x^2*x^2-4=0

Wy multiply elements

-3x^2+5x^4-4=0

We do not support expression: x^4

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